What is the derivative of sin(9x)+cos(2x) ?

The derivative of sin(9x)+cos(2x) is cos(9x)*9-sin(2x)*2

What is the first derivative of sin(9x)+cos(2x) ?

The first derivative of sin(9x)+cos(2x) is cos(9x)*9-sin(2x)*2

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derivative of

sin (9 x) + cos (2 x)

cos (9 x) \cdot 9 - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (9 x) + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (9 x)) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (sin (9 x)) = cos (9 x) \cdot 9

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= cos (9 x) \cdot 9 - sin (2 x) \cdot 2

\int \frac{1 - z}{- 1 - z}

(ln (x))^{^{'}}

\int (x^{2} - 2 x - 3) d x

(x^{2} + 1) y^{^{'}} + y^{2} + 1 = 0, y (4) = e

\int \frac{1}{( sin ( x ) ) ^{2} ( cos ( x ) ) ^{4}} d x

What is the derivative of sin(9x)+cos(2x) ?
The derivative of sin(9x)+cos(2x) is cos(9x)*9-sin(2x)*2
What is the first derivative of sin(9x)+cos(2x) ?
The first derivative of sin(9x)+cos(2x) is cos(9x)*9-sin(2x)*2