What is the solution for y^'=(xy^3)/(25),y(0)=10 ?

The solution for y^'=(xy^3)/(25),y(0)=10 is y=sqrt(-(100)/(4x^2-1))

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y^'=(xy^3)/(25),y(0)=10

y^{^{'}} = \frac{x y ^{3}}{25}, y (0) = 10

y = - \frac{100}{4 x ^{2} - 1}

Solution steps

y^{'} (x) = \frac{x y ^{3}}{25}

Solve separable ODE:

y = - \frac{100}{4 x ^{2} - 1}

y = - \frac{100}{4 x ^{2} - 1}

9 y^{^{''}} - 18 y^{^{'}} + 15 y = 0

x \to 0 lim \frac{x ^{2} + p ^{2} - p}{x ^{2} + q ( x ) ^{2} - q ( x )}

3 sin (x)

\frac{2}{4 - x}

\int - 2 t d t

What is the solution for y^'=(xy^3)/(25),y(0)=10 ?
The solution for y^'=(xy^3)/(25),y(0)=10 is y=sqrt(-(100)/(4x^2-1))