What is the derivative of ln(17x) ?

The derivative of ln(17x) is 1/x

What is the first derivative of ln(17x) ?

The first derivative of ln(17x) is 1/x

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\frac{d}{d x} (ln (17 x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (17 x))

Apply the chain rule:

\frac{1}{17 x} \frac{d}{d x} (17 x)

= \frac{1}{17 x} \frac{d}{d x} (17 x)

\frac{d}{d x} (17 x) = 17

= \frac{1}{17 x} \cdot 17

Simplify

\frac{1}{17 x} \cdot 17 : \frac{1}{x}

= \frac{1}{x}

x \to - 5 lim (3 x - ∣ x + 5 ∣)

y = \frac{1}{x - 2}, at x = 5

\int_{0}^{3} ln (x + 1) d x

\int (1 - x)^{n} d x

n = 0 \sum \infty e^{- 5 n}

What is the derivative of ln(17x) ?
The derivative of ln(17x) is 1/x
What is the first derivative of ln(17x) ?
The first derivative of ln(17x) is 1/x