What is the integral of sec(6w)tan(6w) ?

The integral of sec(6w)tan(6w) is 1/6 sec(6w)+C

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integral of sec(6w)tan(6w)

\int sec (6 w) tan (6 w) d w

\frac{1}{6} sec (6 w) + C

Solution steps

\int sec (6 w) tan (6 w) d w

Apply u-substitution

: \int \frac{1}{6} d u

= \int \frac{1}{6} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{6} u

Substitute back

u = sec (6 w)

= \frac{1}{6} sec (6 w)

Add a constant to the solution

= \frac{1}{6} sec (6 w) + C

\int 2 x - x d x

y = x + 5, at x = 11

\frac{8 ( 4 ^{x} )}{x ^{4}}

\int_{- 1}^{4} x - 2 x^{2} d x

\frac{\partial}{\partial x} (x y e^{y})

What is the integral of sec(6w)tan(6w) ?
The integral of sec(6w)tan(6w) is 1/6 sec(6w)+C