What is the derivative of x^2+x+2 ?

The derivative of x^2+x+2 is 2x+1

What is the first derivative of x^2+x+2 ?

The first derivative of x^2+x+2 is 2x+1

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\frac{d}{d x} (x^{2} + x + 2)

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

\frac{d y}{d x}, 2 x^{2} + y^{2} - 7 = 0

\int \frac{1}{x ^{2} + 2 x + 26} d x

(- 12, 0), (- 15, - 3)

\frac{d y}{d x} = - 2 x y

What is the derivative of x^2+x+2 ?
The derivative of x^2+x+2 is 2x+1
What is the first derivative of x^2+x+2 ?
The first derivative of x^2+x+2 is 2x+1