What is the integral of 7sqrt(16-2x)-14 ?

The integral of 7sqrt(16-2x)-14 is -7/3 (16-2x)^{3/2}-14x+C

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integral of 7sqrt(16-2x)-14

\int 7 16 - 2 x - 14 d x

- \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x + C

Solution steps

\int 7 16 - 2 x - 14 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 16 - 2 x d x - \int 14 d x

\int 7 16 - 2 x d x = - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}}

\int 14 d x = 14 x

= - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x

Add a constant to the solution

= - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x + C

x \to - 7 - lim (\frac{x + 6}{x + 7})

n = 1 \sum \infty (\frac{x}{2})^{n}

\int (x + 3) (x - 7) d x

x^{2} - 3, 5 - x^{2}

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} + x y^{2} + 1)

What is the integral of 7sqrt(16-2x)-14 ?
The integral of 7sqrt(16-2x)-14 is -7/3 (16-2x)^{3/2}-14x+C