What is the derivative of 3x^{2/3}-2x ?

The derivative of 3x^{2/3}-2x is 2/(x^{1/3)}-2

What is the first derivative of 3x^{2/3}-2x ?

The first derivative of 3x^{2/3}-2x is 2/(x^{1/3)}-2

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derivative of

3 x^{\frac{2}{3}} - 2 x

\frac{2}{x ^{\frac{1}{3}}} - 2

Solution steps

\frac{d}{d x} (3 x^{\frac{2}{3}} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{2}{3}}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{\frac{2}{3}}) = \frac{2}{x ^{\frac{1}{3}}}

\frac{d}{d x} (2 x) = 2

= \frac{2}{x ^{\frac{1}{3}}} - 2

\frac{s}{s + 1 0 ^{4}}

\int 6 x^{\frac{3}{5}} d x

\int_{1}^{e^{2}} \frac{ln ^{7} ( x ^{2} )}{x} d x

\frac{d}{d x} (x - sin (x))

arctan (5 x)

What is the derivative of 3x^{2/3}-2x ?
The derivative of 3x^{2/3}-2x is 2/(x^{1/3)}-2
What is the first derivative of 3x^{2/3}-2x ?
The first derivative of 3x^{2/3}-2x is 2/(x^{1/3)}-2