What is the integral from-infinity to 0 of 1/(2-9x) ?

The integral from-infinity to 0 of 1/(2-9x) is diverges

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integral from-infinity to 0 of 1/(2-9x)

\int_{- \infty}^{0} \frac{1}{2 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{2 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{2 - 9 x} d x = - \frac{1}{9} ln ∣ 2 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{2 - 9 x} d x =

diverges

= diverges

\frac{d}{d x} (3 x^{2} + 9 x + 2)

\frac{d y}{d x} = 0

\int \frac{e ^{x + 3}}{x + 3} d x

y = - \frac{1}{2} x^{2} + 2, y = 0

What is the integral from-infinity to 0 of 1/(2-9x) ?
The integral from-infinity to 0 of 1/(2-9x) is diverges