What is the integral from 1 to sqrt(2 of)x ?

The integral from 1 to sqrt(2 of)x is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to sqrt(2 of)x

\int_{1}^{2} x d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\frac{\partial}{\partial z} (arctan (\frac{y}{x}))

\int \frac{1}{x ^{2} \cdot 9 - x ^{2}} d x

\int \frac{x ^{2} - x + 10}{( x + 2 ) ( x ^{2} + 4 )} d x

\frac{\partial}{\partial x} (2 x^{3} + x^{2} y^{3} - 3 y^{2})

\frac{d y}{d x} = \frac{cos ( 14 x )}{e ^{14 y}}

What is the integral from 1 to sqrt(2 of)x ?
The integral from 1 to sqrt(2 of)x is 1/2