What is the derivative of 2x^3-5 ?

The derivative of 2x^3-5 is 6x^2

What is the first derivative of 2x^3-5 ?

The first derivative of 2x^3-5 is 6x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

2 x^{3} - 5

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (5) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

x \to - 1 - lim (\frac{1}{x - 1} + e^{x})

\frac{d}{d t} (3 t)

\int \frac{( x ^{2} + 2 x + 1 )}{( x + 3 )} d x

\frac{d y}{d t} = y^{2} - 4

f (x) = 7 x + 1