What is (\partial)/(\partial x)(sin(x+2y+3z)) ?

The answer to (\partial)/(\partial x)(sin(x+2y+3z)) is cos(x+2y+3z)

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(\partial)/(\partial x)(sin(x+2y+3z))

\frac{\partial}{\partial x} (sin (x + 2 y + 3 z))

cos (x + 2 y + 3 z)

Solution steps

\frac{\partial}{\partial x} (sin (x + 2 y + 3 z))

Treat

y, z

as constants

Apply the chain rule:

cos (x + 2 y + 3 z) \frac{\partial}{\partial x} (x + 2 y + 3 z)

= cos (x + 2 y + 3 z) \frac{\partial}{\partial x} (x + 2 y + 3 z)

\frac{\partial}{\partial x} (x + 2 y + 3 z) = 1

= cos (x + 2 y + 3 z) \cdot 1

Simplify

= cos (x + 2 y + 3 z)

f (x) = \frac{4 x}{3 x ^{2} + 1}

x \to 4 lim (\frac{7}{( x - 4 )})

\frac{\partial}{\partial x} (y ln (x y))

x \to 2 lim (\frac{6}{( x - 2 ) ^{3}})

\frac{d y}{d x}, 7 x + 4 y = 8

What is (\partial)/(\partial x)(sin(x+2y+3z)) ?
The answer to (\partial)/(\partial x)(sin(x+2y+3z)) is cos(x+2y+3z)