What is the (e^{-1/(x^2)})^' ?

The (e^{-1/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)

What is the first (e^{-1/(x^2)})^' ?

The first (e^{-1/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)

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(e^{- \frac{1}{x ^{2}}})^{^{'}}

\frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

Solution steps

(e^{- \frac{1}{x ^{2}}})^{'}

Apply the chain rule:

e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

= e^{- \frac{1}{x ^{2}}} (- \frac{1}{x ^{2}})^{'}

(- \frac{1}{x ^{2}})^{'} = \frac{2}{x ^{3}}

= e^{- \frac{1}{x ^{2}}} \frac{2}{x ^{3}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 e ^{- \frac{1}{x ^{2}}}}{x ^{3}}

\int \frac{e ^{x}}{e ^{2 x} + 1} d x

\int_{2}^{3} \frac{5}{3 - x} d x

\frac{\partial}{\partial x} (x^{2} \cdot y^{3})

\int x (x + a) (x + b) d x

y^{^{''}} + 20 y^{^{'}} + 500 = 12

What is the (e^{-1/(x^2)})^' ?
The (e^{-1/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)
What is the first (e^{-1/(x^2)})^' ?
The first (e^{-1/(x^2)})^' is (2e^{-1/(x^2)})/(x^3)