What is laplacetransform 2cos(t) ?

The answer to laplacetransform 2cos(t) is (2s)/(s^2+1)

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laplacetransform 2cos(t)

laplace transform

2 cos (t)

\frac{2 s}{s ^{2} + 1}

Solution steps

L {2 cos (t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {cos (t)}

L {cos (t)} : \frac{s}{s ^{2} + 1}

= 2 \cdot \frac{s}{s ^{2} + 1}

Refine

2 \frac{s}{s ^{2} + 1} : \frac{2 s}{s ^{2} + 1}

= \frac{2 s}{s ^{2} + 1}

2 x^{2} y^{^{''}} + 5 x y^{^{'}} + y = x^{2} - x

\frac{s}{( s ^{2} + 2 s + 2 )}

y^{^{'}} - \frac{1}{t} y = 0

\frac{d y}{d x} = x (7 - y)

n = 0 \sum \infty sin (πn)

What is laplacetransform 2cos(t) ?
The answer to laplacetransform 2cos(t) is (2s)/(s^2+1)