What is the integral from-2 to 1 of 1/(sqrt(2-x)) ?

The integral from-2 to 1 of 1/(sqrt(2-x)) is 2

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integral from-2 to 1 of 1/(sqrt(2-x))

\int_{- 2}^{1} \frac{1}{2 - x} d x

2

Solution steps

\int_{- 2}^{1} \frac{1}{2 - x} d x

Apply u-substitution

: \int_{4}^{1} - \frac{1}{u} d u

= \int_{4}^{1} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{4} - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{1}^{4} \frac{1}{u} d u)

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{1}^{4}

= - (- [2 u^{\frac{1}{2}}]_{1}^{4})

Simplify

- (- [2 u^{\frac{1}{2}}]_{1}^{4}) : [2 u]_{1}^{4}

= [2 u]_{1}^{4}

Compute the boundaries:

2

= 2

\frac{d}{d x} (x e^{- 6 x})

tan (e^{5 t}) + e^{t a n (5 t)}

k = 2 \sum \infty \frac{3}{2 ^{k}}

\frac{\partial}{\partial y} (e^{2 x - 3 y})

\frac{\partial}{\partial x} (y^{2} + x)

What is the integral from-2 to 1 of 1/(sqrt(2-x)) ?
The integral from-2 to 1 of 1/(sqrt(2-x)) is 2