What is the derivative of 64e^{4x} ?

The derivative of 64e^{4x} is 256e^{4x}

What is the first derivative of 64e^{4x} ?

The first derivative of 64e^{4x} is 256e^{4x}

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\frac{d}{d x} (64 e^{4 x})

256 e^{4 x}

Solution steps

\frac{d}{d x} (64 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 64 e^{4 x} \cdot 4

Simplify

= 256 e^{4 x}

\frac{d}{d x} (ccos t + t^{2} sin (t))

x^{2} + 2 x + 11, - 4 x + 2, 0

f (x) = 8 x e^{9 x}

\int (cos (x) + \frac{1}{5} x) d x

\int \frac{x ^{3}}{1 + x ^{4}} d x

What is the derivative of 64e^{4x} ?
The derivative of 64e^{4x} is 256e^{4x}
What is the first derivative of 64e^{4x} ?
The first derivative of 64e^{4x} is 256e^{4x}