What is the derivative of 2sin(x-2) ?

The derivative of 2sin(x-2) is 2cos(x-2)

What is the first derivative of 2sin(x-2) ?

The first derivative of 2sin(x-2) is 2cos(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 sin (x - 2))

2 cos (x - 2)

Solution steps

\frac{d}{d x} (2 sin (x - 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (x - 2))

Apply the chain rule:

cos (x - 2) \frac{d}{d x} (x - 2)

= cos (x - 2) \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 2 cos (x - 2) \cdot 1

Simplify

= 2 cos (x - 2)

\frac{d}{d x} (9 - x^{\frac{2}{3}})

(cos^{3} (x))^{^{'}}

f (x) = \frac{2}{x}, at x = - 4

\int \frac{x ^{3}}{x ^{4} - 5} d x

\int \frac{x ^{2} - 18 x + 32}{x ( x - 4 ) ^{2}} d x

What is the derivative of 2sin(x-2) ?
The derivative of 2sin(x-2) is 2cos(x-2)
What is the first derivative of 2sin(x-2) ?
The first derivative of 2sin(x-2) is 2cos(x-2)