What is the solution for y^{''}+13y=0 ?

The solution for y^{''}+13y=0 is y=c_{1}cos(sqrt(13)t)+c_{2}sin(sqrt(13)t)

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y^{''}+13y=0

y^{^{''}} + 13 y = 0

y = c_{1} cos (13 t) + c_{2} sin (13 t)

Solution steps

y^{''} (t) + 13 y = 0

Solve linear ODE:

y = c_{1} cos (13 t) + c_{2} sin (13 t)

y = c_{1} cos (13 t) + c_{2} sin (13 t)

\frac{d y}{d x} = \frac{x + x y ^{2}}{4 y}

\int_{0}^{\frac{3 π}{2}} cos^{3} (17 x) d x

y = x + 1, x = 8

\int x^{2} - 2 x + 2 d x

f (x) = \frac{1 - cos ( x )}{sin ( x )}

What is the solution for y^{''}+13y=0 ?
The solution for y^{''}+13y=0 is y=c_{1}cos(sqrt(13)t)+c_{2}sin(sqrt(13)t)