What is the derivative of 1/(2x^2-2x+1) ?

The derivative of 1/(2x^2-2x+1) is -(4x-2)/((2x^2-2x+1)^2)

What is the first derivative of 1/(2x^2-2x+1) ?

The first derivative of 1/(2x^2-2x+1) is -(4x-2)/((2x^2-2x+1)^2)

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\frac{d}{d x} (\frac{1}{2 x ^{2} - 2 x + 1})

- \frac{4 x - 2}{( 2 x ^{2} - 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x ^{2} - 2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x^{2} - 2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x ^{2} - 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x^{2} - 2 x + 1)

= - \frac{1}{( 2 x ^{2} - 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x^{2} - 2 x + 1)

\frac{d}{d x} (2 x^{2} - 2 x + 1) = 4 x - 2

= - \frac{1}{( 2 x ^{2} - 2 x + 1 ) ^{2}} (4 x - 2)

Simplify

- \frac{1}{( 2 x ^{2} - 2 x + 1 ) ^{2}} (4 x - 2) : - \frac{4 x - 2}{( 2 x ^{2} - 2 x + 1 ) ^{2}}

= - \frac{4 x - 2}{( 2 x ^{2} - 2 x + 1 ) ^{2}}

x \to \infty lim (π 5^{x})

y = x^{2} - 2 x, y = - x^{4}

y = 7 x^{3} + 2

\int (t + 200)^{2} d t

\frac{d}{d x} (\frac{2 - x e ^{x}}{x + e ^{x}})

What is the derivative of 1/(2x^2-2x+1) ?
The derivative of 1/(2x^2-2x+1) is -(4x-2)/((2x^2-2x+1)^2)
What is the first derivative of 1/(2x^2-2x+1) ?
The first derivative of 1/(2x^2-2x+1) is -(4x-2)/((2x^2-2x+1)^2)