What is the limit as x approaches 0 of (x+2)/(x^3+8) ?

The limit as x approaches 0 of (x+2)/(x^3+8) is 1/4

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limit as x approaches 0 of (x+2)/(x^3+8)

x \to 0 lim (\frac{x + 2}{x ^{3} + 8})

\frac{1}{4}

Solution steps

x \to 0 lim (\frac{x + 2}{x ^{3} + 8})

Plug in the value

x = 0

= \frac{0 + 2}{0 ^{3} + 8}

Simplify

\frac{0 + 2}{0 ^{3} + 8} : \frac{1}{4}

= \frac{1}{4}

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What is the limit as x approaches 0 of (x+2)/(x^3+8) ?
The limit as x approaches 0 of (x+2)/(x^3+8) is 1/4