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Popular >

x^2y^'-xy=y^2

Solution

x^{2} y^{^{'}} - x y = y^{2}

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) - x y = y^{2}

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

Popular Examples

(\partial)/(\partial y)(sqrt(y))

\frac{\partial}{\partial y} (y)

4/3 xy^'-3/8 y=0

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integral of 2xcos(3x)

\int 2 x cos (3 x) d x

derivative of 2xln(3x-4)derivative of

2 x ln (3 x - 4)

slope of (-17,-13),(-9,7)slope

(- 17, - 13), (- 9, 7)

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-xy=y^2 ?
The solution for x^2y^'-xy=y^2 is y= x/(-ln(x)+c_{1)}