What is the sum from n=1 to infinity of 1/(3n^2+2) ?

The sum from n=1 to infinity of 1/(3n^2+2) is converges

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sum from n=1 to infinity of 1/(3n^2+2)

n = 1 \sum \infty \frac{1}{3 n ^{2} + 2}

converges

Solution steps

n = 1 \sum \infty \frac{1}{3 n ^{2} + 2}

Apply Series Comparison Test:

converges

= converges

\frac{d}{d x} (\frac{2 cos ( x ) - 3}{sin ( x )})

x \to 0 lim (1 - \frac{cos ( 5 x )}{x})

(2.3) (4.3)

\frac{d}{d x} (- 12 x sin (x^{2}) - 8 x^{3} cos (x^{2}))

x \to π lim (tan (x))

What is the sum from n=1 to infinity of 1/(3n^2+2) ?
The sum from n=1 to infinity of 1/(3n^2+2) is converges