What is the solution for x^2y^{''}+7xy^'+8y= 6/x ?

The solution for x^2y^{''}+7xy^'+8y= 6/x is y=(c_{1})/(x^2)+(c_{2})/(x^4)+2/x

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x^2y^{''}+7xy^'+8y= 6/x

x^{2} y^{^{''}} + 7 x y^{^{'}} + 8 y = \frac{6}{x}

y = \frac{c _{1}}{x ^{2}} + \frac{c _{2}}{x ^{4}} + \frac{2}{x}

Solution steps

x^{2} y^{''} (x) + 7 x y^{'} (x) + 8 y = \frac{6}{x}

Solve linear ODE:

y = \frac{c _{1}}{x ^{2}} + \frac{c _{2}}{x ^{4}} + \frac{2}{x}

y = \frac{c _{1}}{x ^{2}} + \frac{c _{2}}{x ^{4}} + \frac{2}{x}

f (x) = 8 x^{4}

\int \frac{( 6 + 6 x )}{1 + x ^{2}} d x

\int x^{2} cos (x) + 2 sin (x) d x

\int_{- \infty}^{0} x e^{7 x} d x

\int 21 e^{42 x} arctan (e^{21 x}) d x

What is the solution for x^2y^{''}+7xy^'+8y= 6/x ?
The solution for x^2y^{''}+7xy^'+8y= 6/x is y=(c_{1})/(x^2)+(c_{2})/(x^4)+2/x