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Popular >

area x,2-x,0

Solution

area

x, 2 - x, 0

Solution

1

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = 2 - x : x = 1

x = 0 : x = 0

2 - x = 0 : x = 2

= \int_{0}^{1} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{1}^{2} ∣ f_{3} (x) - f_{2} (x) ∣ d x

= \int_{0}^{1} ∣ x - 0 ∣ d x + \int_{1}^{2} ∣ 0 - (2 - x) ∣ d x

\int_{0}^{1} ∣ x - 0 ∣ d x = \frac{1}{2}

\int_{1}^{2} ∣ 0 - (2 - x) ∣ d x = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

= 1

Popular Examples

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limit as x approaches 0 of (2x-2)/x

x \to 0 lim (\frac{2 x - 2}{x})

(\partial)/(\partial y)(1+x^4+y^4)

\frac{\partial}{\partial y} (1 + x^{4} + y^{4})

y^{^{''}} + y = 2 x e^{x}

derivative of ln(6-x)

\frac{d}{d x} (ln (6 - x))

Frequently Asked Questions (FAQ)

What is area x,2-x,0 ?
The answer to area x,2-x,0 is 1