What is (\partial)/(\partial x)(4x^2y^3) ?

The answer to (\partial)/(\partial x)(4x^2y^3) is 8xy^3

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(\partial)/(\partial x)(4x^2y^3)

\frac{\partial}{\partial x} (4 x^{2} y^{3})

8 x y^{3}

Solution steps

\frac{\partial}{\partial x} (4 x^{2} y^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 y^{3} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 y^{3} \cdot 2 x^{2 - 1}

Simplify

= 8 x y^{3}

\int \frac{4 x}{4 x ^{4} + 9} d x

y = 3 x, y = 2 x - 3, y = 0

\int \frac{( x - b ) ^{2}}{x} d x

\int_{- 1}^{1} (x + 1)^{2} d x

\int 700 x 3 + 2 x d x

What is (\partial)/(\partial x)(4x^2y^3) ?
The answer to (\partial)/(\partial x)(4x^2y^3) is 8xy^3