What is the derivative of 16sin(2x) ?

The derivative of 16sin(2x) is 32cos(2x)

What is the first derivative of 16sin(2x) ?

The first derivative of 16sin(2x) is 32cos(2x)

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\frac{d}{d x} (16 sin (2 x))

32 cos (2 x)

Solution steps

\frac{d}{d x} (16 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 16 cos (2 x) \cdot 2

Simplify

= 32 cos (2 x)

\frac{1}{2 s ^{2} + 4 s + 3}

y^{^{'}} + 4 y = 3 sin (e^{4 x})

\int \frac{4 x ^{2} - 16}{x} d x

\frac{d}{d x} ((tan (x))^{- 1})

\int sec^{2} (x) tan^{4} (x) d x

What is the derivative of 16sin(2x) ?
The derivative of 16sin(2x) is 32cos(2x)
What is the first derivative of 16sin(2x) ?
The first derivative of 16sin(2x) is 32cos(2x)