What is the solution for y^'+1/3 y=e^xy^4 ?

The solution for y^'+1/3 y=e^xy^4 is y=\sqrt[3]{1/(e^x(-3x+c_{1))}}

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y^'+1/3 y=e^xy^4

y^{^{'}} + \frac{1}{3} y = e^{x} y^{4}

Solution steps

y^{'} (x) + \frac{1}{3} y = e^{x} y^{4}

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What is the solution for y^'+1/3 y=e^xy^4 ?
The solution for y^'+1/3 y=e^xy^4 is y=\sqrt[3]{1/(e^x(-3x+c_{1))}}