What is the first derivative of 3-4x ?

The first derivative of 3-4x is -4

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derivative of 3-4x

\frac{d}{d x} (3 - 4 x)

- 4

Solution steps

\frac{d}{d x} (3 - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (4 x)

\frac{d}{d x} (3) = 0

\frac{d}{d x} (4 x) = 4

= 0 - 4

Simplify

= - 4

- 4

f (x) = e^{x^{2} - 4} + 2 x + 9

\int e^{i 8 x} cos (3 x) d x

\int_{1}^{2} (\frac{x}{2} - \frac{2}{x}) d x

\frac{5 e ^{- s}}{( s ^{2} - 2 s + 1 )}