What is the tangent of f(x)=(x^4-2x+8)^6,\at x=1 ?

The tangent of f(x)=(x^4-2x+8)^6,\at x=1 is y=201684x-84035

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(x^4-2x+8)^6,\at x=1

tangent of

f (x) = (x^{4} - 2 x + 8)^{6}, at x = 1

y = 201684 x - 84035

Solution steps

Find the tangent point:

(1, 117649)

Find the slope of

f (x) = (x^{4} - 2 x + 8)^{6} : \frac{df ( x )}{d x} = 6 (x^{4} - 2 x + 8)^{5} (4 x^{3} - 2)

Compute the slope of

f (x) = (x^{4} - 2 x + 8)^{6}

x = 1 : m = 201684

Find the line with slope m=

201684

and passing through

(1, 117649) : y = 201684 x - 84035

y = 201684 x - 84035

\int e^{x^{2}} 2 x^{3} d x

x \to \infty lim (- 5)

f (t) = arcsin (8 t)

y = (x^{2} + 1)^{3} (x - 1)

\int e^{\frac{1}{2 x}} d x

What is the tangent of f(x)=(x^4-2x+8)^6,\at x=1 ?
The tangent of f(x)=(x^4-2x+8)^6,\at x=1 is y=201684x-84035