What is the derivative of sqrt(2+x^2) ?

The derivative of sqrt(2+x^2) is x/(sqrt(2+x^2))

What is the first derivative of sqrt(2+x^2) ?

The first derivative of sqrt(2+x^2) is x/(sqrt(2+x^2))

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derivative of

2 + x^{2}

\frac{x}{2 + x ^{2}}

Solution steps

\frac{d}{d x} (2 + x^{2})

Apply the chain rule:

\frac{1}{2 2 + x ^{2}} \frac{d}{d x} (2 + x^{2})

= \frac{1}{2 2 + x ^{2}} \frac{d}{d x} (2 + x^{2})

\frac{d}{d x} (2 + x^{2}) = 2 x

= \frac{1}{2 2 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 2 + x ^{2}} \cdot 2 x : \frac{x}{2 + x ^{2}}

= \frac{x}{2 + x ^{2}}

n = 0 \sum \infty 2 (- \frac{2}{3})^{n}

\frac{1}{3} x^{3} - 3 x^{2} - 16 x + 8

y^{^{'}} cot^{2} (x) + tan (y) = 0

\int_{- 3}^{3} x^{2} d x

y^{^{'}} = - 1 - 4 x + 2 y, y (0) = 5

What is the derivative of sqrt(2+x^2) ?
The derivative of sqrt(2+x^2) is x/(sqrt(2+x^2))
What is the first derivative of sqrt(2+x^2) ?
The first derivative of sqrt(2+x^2) is x/(sqrt(2+x^2))