What is (\partial)/(\partial x)(x^3+y^4) ?

The answer to (\partial)/(\partial x)(x^3+y^4) is 3x^2

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(\partial)/(\partial x)(x^3+y^4)

\frac{\partial}{\partial x} (x^{3} + y^{4})

3 x^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} + y^{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) + \frac{\partial}{\partial x} (y^{4})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (y^{4}) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\frac{d}{d x} (- sin (a x) a)

\frac{d y}{d x} + 3 x e^{y} = 0

\int cos (a - x) d x

f (x) = x^{3} - 4 x, (- 2, 0)

n = 1 \sum \infty \frac{1}{4 ^{n + 1}}

What is (\partial)/(\partial x)(x^3+y^4) ?
The answer to (\partial)/(\partial x)(x^3+y^4) is 3x^2