What is the derivative of f(x)=8x^4+9x ?

The derivative of f(x)=8x^4+9x is 32x^3+9

What is the first derivative of f(x)=8x^4+9x ?

The first derivative of f(x)=8x^4+9x is 32x^3+9

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derivative of

f (x) = 8 x^{4} + 9 x

32 x^{3} + 9

Solution steps

\frac{d}{d x} (8 x^{4} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{4}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (8 x^{4}) = 32 x^{3}

\frac{d}{d x} (9 x) = 9

= 32 x^{3} + 9

n = 1 \sum \infty cos (πn)

f (x) = e^{5 x}, at x = \frac{1}{5} ln (2)

\frac{\partial}{\partial x} (96 - 5 x^{2} - 3 y^{2})

f (x) = x^{3} + 1

\int \frac{e ^{x}}{e ^{3 x} + e ^{2 x}} d x

What is the derivative of f(x)=8x^4+9x ?
The derivative of f(x)=8x^4+9x is 32x^3+9
What is the first derivative of f(x)=8x^4+9x ?
The first derivative of f(x)=8x^4+9x is 32x^3+9