What is (\partial)/(\partial y)(3x^2y^2+2) ?

The answer to (\partial)/(\partial y)(3x^2y^2+2) is 6x^2y

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(\partial)/(\partial y)(3x^2y^2+2)

\frac{\partial}{\partial y} (3 x^{2} y^{2} + 2)

6 x^{2} y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y^{2} + 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y^{2}) + \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (3 x^{2} y^{2}) = 6 x^{2} y

\frac{\partial}{\partial y} (2) = 0

= 6 x^{2} y + 0

Simplify

= 6 x^{2} y

n = 1 \sum \infty \frac{n}{( n ^{3} + 1 )}

x^{2} + 2 x + 3

x \to 2 lim ((x + 3)^{5 x})

y = 7 x^{2} + 2 x + 1

\frac{d y}{d x} = - \frac{x}{y}, y (0) = 0

What is (\partial)/(\partial y)(3x^2y^2+2) ?
The answer to (\partial)/(\partial y)(3x^2y^2+2) is 6x^2y