What is area y=-3x^3+x^2+10x,x=-5/3 ,x=2 ?

The answer to area y=-3x^3+x^2+10x,x=-5/3 ,x=2 is 5581/324

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=-3x^3+x^2+10x,x=-5/3 ,x=2

area

y = - 3 x^{3} + x^{2} + 10 x, x = - \frac{5}{3}, x = 2

\frac{5581}{324}

Decimal Notation

17.22530 \dots

Solution steps

Apply the area formula:

\int_{- \frac{5}{3}}^{2} - 3 x^{3} + x^{2} + 10 x d x

Solve

\int_{- \frac{5}{3}}^{2} - 3 x^{3} + x^{2} + 10 x d x : \frac{5581}{324}

The area is:

= \frac{5581}{324}

x \to a lim (x + x - 4)

\frac{d}{d x} (x cos (x) + sin (x))

x \to c lim (5 + 3 (- 2))

\int (2 x + 3) cos (x^{2} + 3 x) d x

\int \frac{( cos ( θ ) - sin ( θ ) )}{cos ^{2} ( θ )} d θ

What is area y=-3x^3+x^2+10x,x=-5/3 ,x=2 ?
The answer to area y=-3x^3+x^2+10x,x=-5/3 ,x=2 is 5581/324