What is the integral of-sin(x)-cos(x) ?

The integral of-sin(x)-cos(x) is cos(x)-sin(x)+C

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integral of-sin(x)-cos(x)

\int - sin (x) - cos (x) d x

cos (x) - sin (x) + C

Solution steps

\int - sin (x) - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int sin (x) d x - \int cos (x) d x

\int sin (x) d x = - cos (x)

\int cos (x) d x = sin (x)

= - (- cos (x)) - sin (x)

Simplify

= cos (x) - sin (x)

Add a constant to the solution

= cos (x) - sin (x) + C

y^{^{''}} - 2 y^{^{'}} - 15 y = - 2

\frac{\partial}{\partial x} (\frac{3 y ^{2} - x ^{2}}{y ^{5}})

\frac{\partial}{\partial y} (e^{y} (x^{2} - y^{2}))

\frac{d}{d x} (\frac{4 x ^{2} + 8 x + 4}{x})

g (u) = 7 u + 5 u

What is the integral of-sin(x)-cos(x) ?
The integral of-sin(x)-cos(x) is cos(x)-sin(x)+C