What is the derivative of t+sqrt(t) ?

The derivative of t+sqrt(t) is 1+1/(2sqrt(t))

What is the first derivative of t+sqrt(t) ?

The first derivative of t+sqrt(t) is 1+1/(2sqrt(t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

t + t

1 + \frac{1}{2 t}

Solution steps

\frac{d}{d t} (t + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} + \frac{d}{d t} (t)

\frac{d t}{d t} = 1

\frac{d}{d t} (t) = \frac{1}{2 t}

= 1 + \frac{1}{2 t}

\frac{d}{d x} (cos (x^{4}) \cdot 4 x^{3})

\frac{d}{d x} (8 8 x^{2} + 3)

y^{^{'}} = \frac{3 x}{y + x ^{2} y}, y (0) = - 3

\frac{\partial}{\partial z} (\frac{1}{z})

\int \frac{w ^{2} + 16}{w ^{2} - 16} d w

What is the derivative of t+sqrt(t) ?
The derivative of t+sqrt(t) is 1+1/(2sqrt(t))
What is the first derivative of t+sqrt(t) ?
The first derivative of t+sqrt(t) is 1+1/(2sqrt(t))