What is area y=e^x,y=7e^{-x}+6,x=0 ?

The answer to area y=e^x,y=7e^{-x}+6,x=0 is 6ln(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=e^x,y=7e^{-x}+6,x=0

area

y = e^{x}, y = 7 e^{- x} + 6, x = 0

6 ln (7)

Decimal Notation

11.67546 \dots

Solution steps

Apply the area formula:

\int_{0}^{l n (7)} e^{x} - (7 e^{- x} + 6) d x

Solve

\int_{0}^{l n (7)} e^{x} - (7 e^{- x} + 6) d x : 6 ln (7)

The area is:

= 6 ln (7)

\int tan^{9} (x) sec^{4} (x) d x

\frac{d}{d x} (1 0^{x^{2}} + lo g_{10} (∣ 2 + 3 x ∣))

\int_{2}^{8} \frac{3}{x} d x

\int_{0}^{0.5} 7 arccos (x) d x

x \to \infty lim (e^{+ x})

What is area y=e^x,y=7e^{-x}+6,x=0 ?
The answer to area y=e^x,y=7e^{-x}+6,x=0 is 6ln(7)