What is the integral of 1/((5x+1)^3) ?

The integral of 1/((5x+1)^3) is -1/(10(5x+1)^2)+C

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integral of 1/((5x+1)^3)

\int \frac{1}{( 5 x + 1 ) ^{3}} d x

- \frac{1}{10 ( 5 x + 1 ) ^{2}} + C

Solution steps

\int \frac{1}{( 5 x + 1 ) ^{3}} d x

Apply u-substitution

: \int \frac{1}{5 u ^{3}} d u

= \int \frac{1}{5 u ^{3}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u ^{3}} d u

Apply the Power Rule

: - \frac{1}{2 u ^{2}}

= \frac{1}{5} (- \frac{1}{2 u ^{2}})

Substitute back

u = 5 x + 1

= \frac{1}{5} (- \frac{1}{2 ( 5 x + 1 ) ^{2}})

Simplify

\frac{1}{5} (- \frac{1}{2 ( 5 x + 1 ) ^{2}}) : - \frac{1}{10 ( 5 x + 1 ) ^{2}}

= - \frac{1}{10 ( 5 x + 1 ) ^{2}}

Add a constant to the solution

= - \frac{1}{10 ( 5 x + 1 ) ^{2}} + C

\frac{d}{d x} (3 x^{4} - 5 x^{2} + 2 3 x)

\int \frac{( 1 + x ^{2} )}{x} d x

\int a x d x

\frac{d}{d x} (sec (x^{3}))

What is the integral of 1/((5x+1)^3) ?
The integral of 1/((5x+1)^3) is -1/(10(5x+1)^2)+C