What is the solution for x^2y^{''}-4xy^'-6y=0 ?

The solution for x^2y^{''}-4xy^'-6y=0 is y=c_{1}x^6+(c_{2})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^{''}-4xy^'-6y=0

x^{2} y^{^{''}} - 4 x y^{^{'}} - 6 y = 0

y = c_{1} x^{6} + \frac{c _{2}}{x}

Solution steps

x^{2} y^{''} (x) - 4 x y^{'} (x) - 6 y = 0

Solve linear ODE:

y = c_{1} x^{6} + \frac{c _{2}}{x}

y = c_{1} x^{6} + \frac{c _{2}}{x}

\frac{5 e ^{x} x ^{\frac{3}{2}}}{2} + e^{x} x^{\frac{5}{2}}

2 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 6 x e^{- y}

\int 3 e^{5} d x

\frac{d}{d x} (\frac{1 + tan ^{2} ( x )}{x sec ( x )})

\int ln (sec (x)) d x

What is the solution for x^2y^{''}-4xy^'-6y=0 ?
The solution for x^2y^{''}-4xy^'-6y=0 is y=c_{1}x^6+(c_{2})/x