What is the tangent of 4x-32sqrt(x),\at x=4 ?

The tangent of 4x-32sqrt(x),\at x=4 is y=-4x-32

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tangent of 4x-32sqrt(x),\at x=4

tangent of

4 x - 32 x, at x = 4

y = - 4 x - 32

Solution steps

Find the tangent point:

(4, - 48)

Find the slope of

y = 4 x - 32 x : \frac{d y}{d x} = 4 - \frac{16}{x}

Compute the slope of

y = 4 x - 32 x

x = 4 : m = - 4

Find the line with slope m=

- 4

and passing through

(4, - 48) : y = - 4 x - 32

y = - 4 x - 32

\int_{- 1}^{1} x^{4} d x

n = 1 \sum \infty n^{4} (1 + n^{5})

\int \frac{x ^{3}}{x ^{8} + 25} d x

\frac{d}{d x} ((1 + x)^{n})

\int \frac{1}{4 - x} d x

What is the tangent of 4x-32sqrt(x),\at x=4 ?
The tangent of 4x-32sqrt(x),\at x=4 is y=-4x-32