What is the derivative of (11x/(2+x^2)) ?

The derivative of (11x/(2+x^2)) is (11(2-x^2))/((2+x^2)^2)

What is the first derivative of (11x/(2+x^2)) ?

The first derivative of (11x/(2+x^2)) is (11(2-x^2))/((2+x^2)^2)

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\frac{d}{d x} (\frac{11 x}{2 + x ^{2}})

\frac{11 ( 2 - x ^{2} )}{( 2 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{11 x}{2 + x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 11 \frac{d}{d x} (\frac{x}{2 + x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 11 \cdot \frac{\frac{d x}{d x} ( 2 + x ^{2} ) - \frac{d}{d x} ( 2 + x ^{2} ) x}{( 2 + x ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (2 + x^{2}) = 2 x

= 11 \cdot \frac{1 \cdot ( 2 + x ^{2} ) - 2 xx}{( 2 + x ^{2} ) ^{2}}

Simplify

11 \cdot \frac{1 \cdot ( 2 + x ^{2} ) - 2 xx}{( 2 + x ^{2} ) ^{2}} : \frac{11 ( 2 - x ^{2} )}{( 2 + x ^{2} ) ^{2}}

= \frac{11 ( 2 - x ^{2} )}{( 2 + x ^{2} ) ^{2}}

\int_{0}^{10} 49 - 9.8 x d x

y = (\frac{x ^{2} + 4}{x ^{2} - 4})^{4}

n = 1 \sum \infty \frac{1}{n ^{2}}

\int_{1}^{2} \frac{5}{x ^{3} + 3 x} d x

\int ((3 x^{5} - 4)^{2} \cdot 5 x^{4}) d x

What is the derivative of (11x/(2+x^2)) ?
The derivative of (11x/(2+x^2)) is (11(2-x^2))/((2+x^2)^2)
What is the first derivative of (11x/(2+x^2)) ?
The first derivative of (11x/(2+x^2)) is (11(2-x^2))/((2+x^2)^2)