What is the solution for y^'=y(1-0.001y) ?

The solution for y^'=y(1-0.001y) is y=-(e^{t+c_{1}})/(1-0.001e^{t+c_{1)}}

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y^'=y(1-0.001y)

y^{^{'}} = y (1 - 0.001 y)

y = - \frac{e ^{t + c_{1}}}{1 - 0.001 e ^{t + c_{1}}}

Solution steps

y^{'} (t) = y (1 - 0.001 y)

Solve separable ODE:

y = - \frac{e ^{t + c_{1}}}{1 - 0.001 e ^{t + c_{1}}}

y = - \frac{e ^{t + c_{1}}}{1 - 0.001 e ^{t + c_{1}}}

\int_{0}^{1} π (x^{2})^{2} d x

\frac{d}{d t} (6 t)

f (x) = \frac{x}{x + 6}, at x = 1

f (x) = 3 sec (x), - \frac{π}{6} \leq x \leq \frac{π}{6}

\frac{d y}{d x} = \frac{( x - 3 )}{y + 1}

What is the solution for y^'=y(1-0.001y) ?
The solution for y^'=y(1-0.001y) is y=-(e^{t+c_{1}})/(1-0.001e^{t+c_{1)}}