What is the derivative of y=e^{x^2+9x+4} ?

The derivative of y=e^{x^2+9x+4} is e^{x^2+9x+4}(2x+9)

What is the first derivative of y=e^{x^2+9x+4} ?

The first derivative of y=e^{x^2+9x+4} is e^{x^2+9x+4}(2x+9)

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derivative of

y = e^{x^{2} + 9 x + 4}

e^{x^{2} + 9 x + 4} (2 x + 9)

Solution steps

\frac{d}{d x} (e^{x^{2} + 9 x + 4})

Apply the chain rule:

e^{x^{2} + 9 x + 4} \frac{d}{d x} (x^{2} + 9 x + 4)

= e^{x^{2} + 9 x + 4} \frac{d}{d x} (x^{2} + 9 x + 4)

\frac{d}{d x} (x^{2} + 9 x + 4) = 2 x + 9

= e^{x^{2} + 9 x + 4} (2 x + 9)

y = 3 x^{2}, y = 16 - x^{2}

\int \frac{2}{5 x 9 - 49 x ^{2}} d x

\frac{d x}{d t} = sin (2 t) - 3 x

\frac{\partial}{\partial y} (sin (y) - x y + y^{2})

\int \frac{1}{( x + 2 ) x ^{2} + 4 x + 3} d x

What is the derivative of y=e^{x^2+9x+4} ?
The derivative of y=e^{x^2+9x+4} is e^{x^2+9x+4}(2x+9)
What is the first derivative of y=e^{x^2+9x+4} ?
The first derivative of y=e^{x^2+9x+4} is e^{x^2+9x+4}(2x+9)