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Popular >

integral of 1/(x+4)

Solution

\int \frac{1}{x + 4} d x

Solution

ln ∣ x + 4 ∣ + C

Solution steps

\int \frac{1}{x + 4} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + 4

= ln ∣ x + 4 ∣

Add a constant to the solution

= ln ∣ x + 4 ∣ + C

Popular Examples

(\partial)/(\partial y)(3(x-y)e^{3y+5x^2})

\frac{\partial}{\partial y} (3 (x - y) e^{3 y + 5 x^{2}})

integral of (sqrt(9-x^2))/x

\int \frac{9 - x ^{2}}{x} d x

integral of sqrt(x^2-8x+25)

\int x^{2} - 8 x + 25 d x

area sqrt(4x+4),[-1,5.25]area

4 x + 4, [- 1, 5.25]

integral of (88)/(x^2-121)

\int \frac{88}{x ^{2} - 121} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(x+4) ?
The integral of 1/(x+4) is ln|x+4|+C