What is the tangent of y=8e^xcos(x),(0,8) ?

The tangent of y=8e^xcos(x),(0,8) is y=8x+8

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tangent of y=8e^xcos(x),(0,8)

tangent of

y = 8 e^{x} cos (x), (0, 8)

y = 8 x + 8

Solution steps

Find the slope of

y = 8 e^{x} cos (x) : \frac{d y}{d x} = 8 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 8 e^{x} cos (x)

(0, 8) : m = 8

Find the line with slope m=

8

and passing through

(0, 8) : y = 8 x + 8

y = 8 x + 8

\frac{\partial}{\partial y} (x^{y^{2}})

\int \frac{1}{x ^{3}} 1 - \frac{1}{x ^{2}} d x

\int_{1}^{2} \frac{1}{x} - x d x

\int cot (y) d y

What is the tangent of y=8e^xcos(x),(0,8) ?
The tangent of y=8e^xcos(x),(0,8) is y=8x+8