What is the derivative of ln(13-x^2) ?

The derivative of ln(13-x^2) is -(2x)/(13-x^2)

What is the first derivative of ln(13-x^2) ?

The first derivative of ln(13-x^2) is -(2x)/(13-x^2)

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\frac{d}{d x} (ln (13 - x^{2}))

- \frac{2 x}{13 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (13 - x^{2}))

Apply the chain rule:

\frac{1}{13 - x ^{2}} \frac{d}{d x} (13 - x^{2})

= \frac{1}{13 - x ^{2}} \frac{d}{d x} (13 - x^{2})

\frac{d}{d x} (13 - x^{2}) = - 2 x

= \frac{1}{13 - x ^{2}} (- 2 x)

Simplify

\frac{1}{13 - x ^{2}} (- 2 x) : - \frac{2 x}{13 - x ^{2}}

= - \frac{2 x}{13 - x ^{2}}

\int (csc^{2} (\frac{x}{2})) d x

y = (t - 5) (t^{2} - 3), (2, - 3)

x \to 0 lim (x^{18} ln (x))

\frac{d}{d x} ((x^{3} - 1)^{100})

23 t

What is the derivative of ln(13-x^2) ?
The derivative of ln(13-x^2) is -(2x)/(13-x^2)
What is the first derivative of ln(13-x^2) ?
The first derivative of ln(13-x^2) is -(2x)/(13-x^2)