What is the solution for y^{''}-5y^'+6y=2et ?

The solution for y^{''}-5y^'+6y=2et is y=c_{1}e^{3t}+c_{2}e^{2t}+(et)/3+(5e)/(18)

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y^{''}-5y^'+6y=2et

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e t

y = c_{1} e^{3 t} + c_{2} e^{2 t} + \frac{e t}{3} + \frac{5 e}{18}

Solution steps

y^{''} (t) - 5 y^{'} (t) + 6 y = 2 e t

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{2 t} + \frac{e t}{3} + \frac{5 e}{18}

y = c_{1} e^{3 t} + c_{2} e^{2 t} + \frac{e t}{3} + \frac{5 e}{18}

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What is the solution for y^{''}-5y^'+6y=2et ?
The solution for y^{''}-5y^'+6y=2et is y=c_{1}e^{3t}+c_{2}e^{2t}+(et)/3+(5e)/(18)