What is area y=2sqrt(x),y=(2x)/3 ?

The answer to area y=2sqrt(x),y=(2x)/3 is 9

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area y=2sqrt(x),y=(2x)/3

area

y = 2 x, y = \frac{2 x}{3}

9

Solution steps

Apply the area formula:

\int_{0}^{9} 2 x - \frac{2 x}{3} d x

Solve

\int_{0}^{9} 2 x - \frac{2 x}{3} d x : 9

The area is:

= 9

\frac{d}{d x} (2 x + y)^{3} = x

\frac{\partial}{\partial x} (cos^{3} (x))

\int \frac{x + 16}{x} d x

x \to - 3 lim (- (3 x))

e^{(3 h^{2} + 6)}