What is the derivative of y^2+x^2-2 ?

The derivative of y^2+x^2-2 is 2x+2y(dy)/(dx)

What is the first derivative of y^2+x^2-2 ?

The first derivative of y^2+x^2-2 is 2x+2y(dy)/(dx)

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\frac{d}{d x} (y^{2} + x^{2} - 2)

2 x + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (y^{2} + x^{2} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2)

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= 2 y \frac{d y}{d x} + 2 x - 0

Simplify

= 2 x + 2 y \frac{d y}{d x}

\int a - x^{2} d x

n = 1 \sum \infty \frac{1}{3 n - 2}

f (x) = 6 x^{l n (x)}

- \frac{5}{x ^{3}}

f (x) = 3 x + 5

What is the derivative of y^2+x^2-2 ?
The derivative of y^2+x^2-2 is 2x+2y(dy)/(dx)
What is the first derivative of y^2+x^2-2 ?
The first derivative of y^2+x^2-2 is 2x+2y(dy)/(dx)