What is the limit as x approaches-3+of 1/(x^2-9) ?

The limit as x approaches-3+of 1/(x^2-9) is -infinity

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limit as x approaches-3+of 1/(x^2-9)

x \to - 3 + lim (\frac{1}{x ^{2} - 9})

- \infty

Solution steps

x \to - 3 + lim (\frac{1}{x ^{2} - 9})

For

x

approaching

- 3

from the right

, x > - 3 \Rightarrow x^{2} - 9 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

(1, - 19), (- 2, - 7)

\int (t ln (t))^{2} d t

\int sin (2 x + y) d x

\int \frac{x x ^{2} + 4}{x ^{2} - 1} d x

f (x) = \frac{x}{4}

What is the limit as x approaches-3+of 1/(x^2-9) ?
The limit as x approaches-3+of 1/(x^2-9) is -infinity