What is the solution for (-14xy^2+19y)+(-14x^2y+19x)y^'=0 ?

The solution for (-14xy^2+19y)+(-14x^2y+19x)y^'=0 is y=(c_{1})/x

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(-14xy^2+19y)+(-14x^2y+19x)y^'=0

(- 14 x y^{2} + 19 y) + (- 14 x^{2} y + 19 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(- 14 x y^{2} + 19 y) + (- 14 x^{2} y + 19 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\int_{1}^{3} x 4^{(x^{2})} d x

6 t

x \to 0 lim (\frac{2 tan ( 2 x )}{x})

n = 0 \sum \infty (\frac{x}{n})^{n}

x \to π - lim (\frac{1}{sin ( x )})

What is the solution for (-14xy^2+19y)+(-14x^2y+19x)y^'=0 ?
The solution for (-14xy^2+19y)+(-14x^2y+19x)y^'=0 is y=(c_{1})/x